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  1. Home
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  3. Gemini 2.5 Pro Preview 06-05
  4. Estimate Complexity

See how Gemini 2.5 Pro Preview 06-05 compares on this challenge:

  • Gemini 2.5 Pro Preview 06-05 vs Claude Sonnet 4.6
  • Gemini 2.5 Pro Preview 06-05 vs Gemini 3.1 Pro Preview
  • Gemini 2.5 Pro Preview 06-05 vs Z.ai: GLM 5

4 models have responded to the "Estimate Complexity" challenge. Compare their approaches side-by-side on RIVAL. This response is part of RIVAL's open dataset of 5,600+ AI model responses.

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Back to Gemini 2.5 Pro Preview 06-05

Estimate Complexity

Gemini 2.5 Pro Preview 06-05's response to the Estimate Complexity challenge.

Gemini 2.5 Pro Preview 06-05
June 5, 2025
Text

?
Prompt

Estimate the total number of FLOPs required to train GPT-3 without searching online. Explain your reasoning step by step.

Gemini 2.5 Pro Preview 06-05
Response

gemini-2.5-pro-preview-06-05 logo
Gemini 2.5 Pro Preview 06-05Estimate Complexity
gemini-2.5-pro-preview-06-05 logo
Gemini 2.5 Pro Preview 06-05

Of course. Here is an estimate of the total number of FLOPs required to train GPT-3, based on my internal kn owledge and first principles, without searching online.

The Logic and Formula

To estimate the computational cost of training a large language model like GPT-3, we can use a well-establis hed formula. The total number of Floating Point Operations (FLOPs) is approximately:

Total FLOPs ≈ 6 × P × D

Let's break down what each part of this formula means:

  • P: The number of parameters in the model. This is the total count of all the weights and biases that the model learns during training.
  • D: The total number of tokens in the training dataset. This represents the volume of data the mo del processes.
  • 6: This is a constant factor that provides a good approximation for transformer-based models. It com es from:
    • Forward Pass (1 × P × D): For each token processed, the number of operations is roughly proporti onal to the number of parameters. A common rule of thumb is 2 * P FLOPs per token for a forward pass (one multiplication and one addition for each parameter). So the total for one pass over the data is 2 * P * D.
    • Backward Pass (2 × Forward Pass): The backward pass (backpropagation), where the model calculate s gradients to update its parameters, is computationally more intensive. It's typically estimated to require about twice the operations of the forward pass. So, 2 * (2 * P * D) = 4 * P * D.
    • Total: Adding the forward and backward pass gives us 2PD + 4PD = 6PD.

Now, let's estimate the values for P and D for GPT-3.


Step-by-Step Estimation

Step 1: Estimate the Number of Parameters (P)

My internal knowledge base indicates that the largest version of GPT-3, which is the one most people refer t o, has a specific number of parameters.

  • P ≈ 175 billion parameters
  • In scientific notation, this is 175 x 10⁹

Step 2: Estimate the Training Dataset Size (D)

GPT-3 was trained on a massive corpus of text data scraped from the internet (like the Common Crawl dataset) , books, and Wikipedia. The key is not the raw size of the dataset, but the number of tokens actually used f or training. My recollection is that the model was trained for a single epoch on a curated dataset.

  • D ≈ 300 billion tokens
  • In scientific notation, this is 300 x 10⁹

Step 3: Perform the Calculation

Now we can plug these estimated values into our formula:

Total FLOPs ≈ 6 × P × D

  1. Substitute the values for P and D: Total FLOPs ≈ 6 × (175 × 10⁹) × (300 × 10⁹)

  2. Multiply the constants first: 6 × 175 = 1050 1050 × 300 = 315,000

  3. Multiply the powers of 10: 10⁹ × 10⁹ = 10¹⁸

  4. Combine the results: Total FLOPs ≈ 315,000 × 10¹⁸

  5. Express this in standard scientific notation: Total FLOPs ≈ 3.15 × 10⁵ × 10¹⁸ = 3.15 × 10²³


Final Estimate and Conclusion

Based on my reasoning and the standard formula for calculating training costs, the estimated number of FLOPs required to train the 175B parameter GPT-3 model is approximately:

3.15 x 10²³ FLOPs

To put this astronomical number into perspective:

  • A petaFLOP is 10¹⁵ FLOPs. Our estimate is 315,000,000 petaFLOPs.
  • If you had a supercomputer that could perform one petaFLOP per second (10¹⁵ FLOPs/sec), it would take ** 3.15 x 10⁸ seconds** to complete the training.
  • There are about 31.5 million seconds in a year, so this is equivalent to roughly 10 years of continu ous computation on that machine.

This calculation demonstrates why training foundational models like GPT-3 requires massive-scale data center s with thousands of GPUs running in parallel for months and is an undertaking that costs millions of dollars . The actual paper from OpenAI stated the training took approximately 3.6 x 10²³ FLOPs, so my estimate i s very close to the reported figure.

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About Gemini 2.5 Pro Preview 06-05

Capabilities

ConversationReasoningCode GenerationAnalysisAgentic Tool Use

Categories

TextCodeImageMultimodal

Specifications

Provider
Google
Released
2025-06-05
Size
XLARGE
Parameters
Not disclosed
Context
1,048,576 tokens

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SAME PROMPT

Claude Sonnet 4.6's version

Same prompt, different result

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Gemini 2.5 Pro Preview 06-05 vs Gemini 3.1 Pro Preview

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