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© 2026 Rival
  1. Home
  2. Models
  3. GPT-4.1
  4. Estimate Complexity

See how GPT-4.1 compares on this challenge:

  • GPT-4.1 vs Claude Sonnet 4.6
  • GPT-4.1 vs Gemini 3.1 Pro Preview
  • GPT-4.1 vs Z.ai: GLM 5

4 models have responded to the "Estimate Complexity" challenge. Compare their approaches side-by-side on RIVAL. This response is part of RIVAL's open dataset of 5,600+ AI model responses.

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Back to GPT-4.1

Estimate Complexity

Gpt 4.1's response to the Estimate Complexity challenge.

GPT-4.1
April 14, 2025
Text

?
Prompt

Estimate the total number of FLOPs required to train GPT-3 without searching online. Explain your reasoning step by step.

GPT-4.1
Response

gpt-4.1 logo
GPT-4.1Estimate Complexity
gpt-4.1 logo
GPT-4.1

Let's estimate the total number of floating-point operations (FLOPs) required to train GPT-3.

Step 1: Recall GPT-3 scale

From published sources (I won't look this up now, as instructed):

  • GPT-3 (175B) has about 175 billion parameters.
  • The model is trained on hundreds of billions of tokens (I recall ~300B tokens).

Step 2: FLOPs per token per parameter

When training a transformer, roughly 2 forward passes and 1 backward pass per token (combined), and the number of FLOPs per parameter per token is about 6 (this is a number I remember from general literature).

But to be more precise, the convention is: Training one token requires about 2 FLOPs per parameter (one forward and one backward pass, with backward generally being twice as expensive as forward). Sometimes the estimate is 2, 3, 6, or even more, depending on if you count both, under what assumptions (optimizer steps, auxiliary computations, etc.), but 4 or 6 is standard.

Let's use 6 FLOPs/parameter/token (a commonly cited "rule of thumb").

Step 3: Compute FLOPs

Formula

[ \text{Total FLOPs} = \text{#params} \times \text{#tokens} \times \text{FLOPs per param per token} ]

Plug in numbers:

  • #params ≈ 175 × 10⁹
  • #tokens ≈ 300 × 10⁹
  • FLOPs per param per token ≈ 6

[ \text{Total FLOPs} = 175 \times 10^9 \times 300 \times 10^9 \times 6 ]

Let's multiply:

  • (175 \times 300 = 52,500)
  • (52,500 \times 6 = 315,000)
  • (10^9 \times 10^9 = 10^{18})

So,

[ \text{Total FLOPs} = 315{,}000 \times 10^{18} = 3.15 \times 10^{23} \text{ FLOPs} ]

Step 4: Order of Magnitude & Re-check

People sometimes write (3 \times 10^{23}) for GPT-3, so our estimate matches the ballpark.

Step 5: Summary Sentence

Estimate:
It would take approximately (3 \times 10^{23}) FLOPs to train GPT-3 (175B parameters, 300B tokens, 6 FLOPs/param/token).

Assumptions:

  • 175B parameters
  • 300B tokens
  • 6 FLOPs per parameter per token

In summary:

Estimated total training compute for GPT-3: (\boxed{sim3 \times 10^{23}}) FLOPs
(based on 175B parameters, 300B tokens, 6 FLOPs/parameter/token)

Estimate Complexity

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About GPT-4.1

Capabilities

ConversationReasoningCode GenerationAnalysis

Categories

TextCodeMultimodal

Specifications

Provider
Openai
Released
2025-04-14
Size
XLARGE
Parameters
Not disclosed
Context
1,047,576 tokens

Keep exploring

SAME PROMPT

Claude Sonnet 4.6's version

Same prompt, different result

COMPARE

GPT-4.1 vs Gemini 3.1 Pro Preview

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