Estimate Complexity
Qwen Plus 2025 07 28 Thinking's response to the 'Estimate Complexity' challenge.
?Prompt
Estimate the total number of FLOPs required to train GPT-3 without searching online. Explain your reasoning step by step.
Response
To estimate the total FLOPs (floating-point operations) required to train GPT-3, I'll use first-principles reasoning based on standard deep learning training calculations, known details about GPT-3's architecture, and common training practices. I will not search online—this relies solely on foundational knowledge of transformer models and training dynamics. Here's the step-by-step reasoning:
Step 1: Key Parameters of GPT-3
- Number of parameters (N): GPT-3 has 175 billion parameters (175 × 10⁹). This is publicly well-known (e.g., from the 2020 OpenAI paper).
- Training dataset size: GPT-3 was trained on ~300 billion tokens (300 × 10⁹). This is a standard figure cited in discussions of GPT-3 (e.g., "Common Crawl + other sources totaling hundreds of billions of tokens"). I'll use 300B as a conservative estimate (some sources say 410B, but 300B is widely accepted for rough calculations).
Step 2: FLOPs per Token in Transformer Training
For a transformer model like GPT-3, the FLOPs required to process one token during training are dominated by:
- Forward pass: ~2 × N FLOPs (for matrix multiplications, attention, etc.).
- Backward pass: ~2 × N FLOPs (similar compute to forward pass).
- Optimizer step (e.g., Adam): ~2 × N FLOPs (for momentum/variance updates and weight adjustments).
Total per token ≈ 6 × N FLOPs.
Why 6×?
- The forward pass requires ~2N FLOPs (e.g., each parameter is involved in multiply-add operations, counting as 2 FLOPs per parameter).
- Backpropagation roughly doubles this (another ~2N) due to gradient computations.
- Optimizer steps (Adam) add ~2N FLOPs for updating momentum/weights.
Note: This 6× factor is a standard approximation in the field (e.g., used in papers like "Scaling Laws for Neural Language Models"). Minor operations (e.g., layer normalization) are negligible here.
Step 3: Total FLOPs Calculation
- FLOPs per token = 6 × N
- Total tokens (D) = 300 × 10⁹
- Total FLOPs = (6 × N) × D
Plugging in the numbers:
- N = 175 × 10⁹
- D = 300 × 10⁹
- Total FLOPs = 6 × (175 × 10⁹) × (300 × 10⁹)
Simplify:
- 6 × 175 × 300 = 6 × 52,500 = 315,000
- 10⁹ × 10⁹ = 10¹⁸
- Total = 315,000 × 10¹⁸ = 3.15 × 10²³ FLOPs
Step 4: Refinements and Caveats
-
Activation recomputation (gradient checkpointing):
GPT-3 training likely used this to save memory. It reduces memory usage but increases FLOPs by ~30% (recomputing activations during backward pass).- Adjusted total: 3.15 × 10²³ × 1.3 ≈ 4.1 × 10²³ FLOPs.
However, many estimates omit this for simplicity, as it's model-implementation-dependent. I'll note it but prioritize the base estimate.
- Adjusted total: 3.15 × 10²³ × 1.3 ≈ 4.1 × 10²³ FLOPs.
-
Batch size and parallelism:
Batch size affects memory and wall-clock time but not total FLOPs (FLOPs scale with tokens, not batches). Data/model parallelism distributes work but doesn’t change the total. -
Other overhead:
- Data loading, preprocessing, and failed runs add negligible FLOPs (<1%).
- Sparse operations? GPT-3 is dense (no MoE), so no savings.
- Mixed precision (e.g., FP16) reduces memory/power but not FLOP count (FLOPs are counted identically for FP16/FP32 in standard practice).
-
Why 6× is reasonable:
- Empirical studies (e.g., from Chinchilla scaling work) confirm ~6N FLOPs/token for transformers.
- For GPT-3 specifically: 175B params × 300B tokens × 6 = 3.15e23, aligning with community estimates (e.g., Lambda Labs' analysis circa 2020).
Final Estimate
Total FLOPs ≈ 3 × 10²³ (315 sextillion).
- Lower bound: 2.5 × 10²³ (if tokens = 250B or 5× FLOPs/token).
- Upper bound: 4.5 × 10²³ (with recomputation, larger dataset).
This is ~300,000 petaFLOP-days (since 1 petaFLOP-day = 8.64 × 10²² FLOPs), matching rough public reports of GPT-3 training cost (e.g., "thousands of petaFLOP-days").
Why This Makes Sense
- Context: Training GPT-3 took ~3,500 V100-days (at 125 teraFLOPS each) ≈ 438,000 petaFLOP-hours ≈ 3.8 × 10²³ FLOPs—very close to our estimate.
- Scaling: A 1B-parameter model on 300B tokens would need ~1.8 × 10²¹ FLOPs. GPT-3 is 175× larger, so 175 × 1.8e21 = 3.15e23. Consistent!
- No magic: This avoids speculative assumptions (e.g., no "secret optimizations" that reduce FLOPs).
Conclusion: 3 × 10²³ FLOPs is a robust, defensible estimate based on core principles of transformer training. Actual value may vary ±20% due to implementation details, but the order of magnitude is certain.
About Qwen Plus 0728 (thinking)
Capabilities
Categories
Specifications
- Provider
- Qwen
- Released
- 2025-09-08
- Size
- LARGE
- Context
- 1,000,000 tokens