Qwen3 Next 80B A3B Thinking
To estimate the total FLOPs (floating-point operations) required to train GPT-3 without external references, I'll break this down step by step using fundamental principles of deep learning training and standard heuristics for Transformer models. This is a classic back-of-the-envelope calculation based on widely accepted knowledge in the field.
Step 1: Understand the key components
Training a large language model like GPT-3 involves:
- Forward pass: Computing predictions from input data.
- Backward pass: Computing gradients for parameter updates.
- Total FLOPs = FLOPs from forward pass + FLOPs from backward pass across all training steps.
For Transformer-based models (like GPT-3), a well-established heuristic exists:
Total FLOPs ≈ 6 × (number of parameters) × (total training tokens)
This formula is derived from:
- Forward pass: ~2 FLOPs per parameter per token (due to matrix multiplications, which involve multiply-add operations).
- Backward pass: ~4 FLOPs per parameter per token (gradient computation is more computationally expensive than the forward pass).
- Total: 2 + 4 = 6 FLOPs per parameter per token.
This heuristic accounts for all major operations (attention mechanisms, feed-forward layers, layer norms, etc.) and includes the sequence length implicitly. Why?
- For a sequence of length $L$, the FLOPs per sequence is ~$6N \times L$.
- Total tokens $T = \text{number of sequences} \times L$, so when you compute total FLOPs = $6N \times L \times (\text{sequences}) = 6N \times T$.
- Thus, $L$ cancels out—only the total tokens processed ($T$) matters.
Step 2: Recall known facts about GPT-3
From publicly documented details (without external searches):
- Number of parameters ($N$): GPT-3 has 175 billion parameters (175 × 10⁹).
- This is a well-known figure from the original GPT-3 paper (Brown et al., 2020).
- Total training tokens ($T$): GPT-3 was trained on ~300 billion tokens (300 × 10⁹).
- This comes from the paper's description of the training data: Common Crawl (45%), WebText2 (18%), books (15%), Wikipedia (4%), and other sources, totaling ~300B tokens.
Step 3: Apply the formula
Plug the values into the heuristic:
$$
\text{Total FLOPs} = 6 \times N \times T = 6 \times (175 \times 10^9) \times (300 \times 10^9)
$$
Break down the math:
- First, compute $N \times T$:
$$ 175 \times 10^9 \times 300 \times 10^9 = (175 \times 300) \times 10^{18} = 52,500 \times 10^{18} = 5.25 \times 10^{22} $$ - Multiply by 6:
$$ 6 \times 5.25 \times 10^{22} = 31.5 \times 10^{22} = 3.15 \times 10^{23} $$
Step 4: Validate the result
- This estimate aligns with widely cited figures in the AI community (e.g., from follow-up papers like "Training Compute-Optimal Large Language Models" by Hoffmann et al.).
- Actual values may vary slightly due to implementation details (e.g., mixed-precision training, optimizer overhead), but 3.15 × 10²³ FLOPs is the standard back-of-the-envelope estimate.
- For context:
- This is equivalent to 315 exaFLOPs (1 exaFLOP = 10¹⁸ FLOPs).
- A single NVIDIA A100 GPU delivers ~19.5 teraFLOPs (10¹² FLOPs) in FP16, so training GPT-3 would require ~16 million A100 GPU-hours (though in reality, it was distributed across thousands of GPUs for weeks).
Why this estimate is reasonable
- The 6N per token heuristic is empirically validated for Transformers.
- Forward pass: ~2N FLOPs/token (matrix multiplications dominate).
- Backward pass: ~4N FLOPs/token (gradient calculations involve extra operations like chain rule).
- Total tokens ($T$) is the correct metric because sequence length cancels out (as shown in Step 1).
- GPT-3’s $N = 175B$ and $T = 300B$ are uncontroversial facts from its original documentation.
Final Answer
The total FLOPs required to train GPT-3 is approximately 3.15 × 10²³ FLOPs (or 315 exaFLOPs). This estimate is derived from first principles and standard deep learning heuristics, without external references.