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Bert-Nebulon Alpha vs Claude 3.7 Sonnet: Which Is Better? [2026 Comparison]
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  3. Bert-Nebulon Alpha vs Claude 3.7 Sonnet
Updated Nov 24, 2025

Bert-Nebulon Alpha vs Claude 3.7 Sonnet

Compare Bert-Nebulon Alpha by OpenRouter against Claude 3.7 Sonnet by Anthropic, in 1 community votes, claude 3.7 sonnet wins 100% of head-to-head duels, tested across 35 shared challenges. Updated April 2026.

Which is better, Bert-Nebulon Alpha or Claude 3.7 Sonnet?

Claude 3.7 Sonnet is the better choice overall, winning 100% of 1 blind community votes on Rival. Compare their real outputs side by side below.

Key Differences Between Bert-Nebulon Alpha and Claude 3.7 Sonnet

Bert-Nebulon Alpha is made by openrouter while Claude 3.7 Sonnet is from anthropic. In community voting, In 1 community votes, Claude 3.7 Sonnet wins 100% of head-to-head duels.

In 1 community votes, Claude 3.7 Sonnet wins 100% of head-to-head duels. Based on blind community voting from the Rival open dataset of 1+ human preference judgments for this pair.

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Bert-Nebulon AlphavsClaude 3.7 Sonnet

35 fights queued

Bert-Nebulon Alpha logo

Why Bert-Nebulon Alpha?

9 months newerNov 2025
Claude 3.7 Sonnet logo

Why Claude 3.7 Sonnet?

Dead even. This one's a coin flip.
Bert-Nebulon AlphaClaude 3.7 Sonnet
Input price
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$3.00/M
Output price
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$15.00/M
Context
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200K
Released
Nov 2025
Feb 2025

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Bert-Nebulon AlphaClaude 3.7 Sonnet
Movie
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The Shawshank Redemption

The Shawshank Redemption

19948.7
Album
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OK Computer

OK Computer

Radiohead
Book
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To Kill a Mockingbird

To Kill a Mockingbird

Harper Lee
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Tokyo

Tokyo

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Portal 2

Portal 2

Shooter, Puzzle4.6
12 / 35
01

Estimate Complexityreasoning

Tests an AI's ability to make educated estimates based on technical knowledge

Bert-Nebulon Alpha

Bert-Nebulon Alpha

Openrouter · Nov 2025text

Estimating the total number of floating-point operations (FLOPs) required to train GPT-3 involves breaking down the training process into its core components and making reasonable assumptions based on the model's architecture and training details. Here's a step-by-step breakdown:


1. Key Parameters of GPT-3

GPT-3 has the following key specifications (from the paper or known details):

  • Model size: 175 billion parameters (weights).
  • Training tokens: ~300 billion tokens (from the paper).
  • Batch size: ~3.2 million tokens per batch (1,536 sequences × 2,048 tokens).
  • Optimizer: Adam (or variant), which involves additional computations per parameter.
  • Training steps: ~300 billion tokens / 3.2 million tokens per batch ≈ 93,750 steps.

2. FLOPs per Forward Pass

For a transformer model, the bulk of computation comes from:

  • Matrix multiplications in the attention and feed-forward layers.
  • Softmax and other non-linear operations (negligible compared to matmuls).

Attention Layer FLOPs

For a single attention head:

  • Query-Key-Value projections: 3 × (d_model × d_k) per token.
  • Attention scores: (sequence_length × d_k) × (d_k × sequence_length) = sequence_length² × d_k.
  • Attention over values: (sequence_length × sequence_length) × (sequence_length × d_k) = sequence_length² × d_k.
  • Output projection: (sequence_length × d_k) × (d_k × d_model) = sequence_length × d_model × d_k.

For h heads, this scales linearly. For GPT-3:

  • d_model = 12,288 (hidden size).
  • h = 96 heads.
  • d_k = d_model / h = 128.
  • Sequence length = 2,048 tokens.

Total FLOPs per attention layer:

  • Projections: 3 × (2,048 × 12,288 × 128) ≈ 9.66 × 10⁹.
  • Attention scores: 96 × (2,048² × 128) ≈ 5.15 × 10¹⁰.
  • Attention over values: 96 × (2,048² × 128) ≈ 5.15 × 10¹⁰.
  • Output projection: 2,048 × 12,288 × 128 ≈ 3.22 × 10⁹.
  • Total per attention layer: ~1.16 × 10¹¹ FLOPs.

GPT-3 has 96 layers, so total attention FLOPs per forward pass: 96 × 1.16 × 10¹¹ ≈ 1.11 × 10¹³ FLOPs.

Feed-Forward Layer FLOPs

Each feed-forward layer has two linear transformations:

  • First: (2,048 × 12,288) × (12,288 × 4 × 12,288) ≈ 1.23 × 10¹² FLOPs.
  • Second: (2,048 × 4 × 12,288) × (4 × 12,288 × 12,288) ≈ 1.23 × 10¹² FLOPs.
  • Total per feed-forward layer: ~2.46 × 10¹² FLOPs.

For 96 layers: 96 × 2.46 × 10¹² ≈ 2.36 × 10¹⁴ FLOPs.

Embedding and Output Layers

  • Embedding lookup: negligible (2,048 × 12,288 ≈ 2.5 × 10⁷ FLOPs).
  • Final projection: 2,048 × 12,288 × vocab_size (50,257) ≈ 1.26 × 10¹² FLOPs.

Total Forward Pass FLOPs

Attention + Feed-forward + Output ≈ 1.11 × 10¹³ + 2.36 × 10¹⁴ + 1.26 × 10¹² ≈ 2.48 × 10¹⁴ FLOPs.


3. FLOPs per Backward Pass

The backward pass typically requires 2× the FLOPs of the forward pass (gradient computation for weights and activations). Thus: Backward pass ≈ 2 × 2.48 × 10¹⁴ ≈ 4.96 × 10¹⁴ FLOPs.


4. Optimizer FLOPs (Adam)

Adam involves:

  • Momentum and variance updates: ~4 FLOPs per parameter (2 for momentum, 2 for variance).
  • Weight update: ~2 FLOPs per parameter.
  • Total per parameter: ~6 FLOPs.

For 175 billion parameters: 175 × 10⁹ × 6 ≈ 1.05 × 10¹² FLOPs per step.


5. Total FLOPs per Training Step

Forward + Backward + Optimizer ≈ 2.48 × 10¹⁴ + 4.96 × 10¹⁴ + 1.05 × 10¹² ≈ 7.45 × 10¹⁴ FLOPs per step.


6. Total Training FLOPs

Total steps = 93,750. Total FLOPs = 93,750 × 7.45 × 10¹⁴ ≈ 6.98 × 10¹⁹ FLOPs.


7. Adjustments and Simplifications

  • Parallelism: GPT-3 was trained on thousands of GPUs, but this doesn't change the total FLOPs (just wall-clock time).
  • Mixed precision: Training in FP16/BF16 reduces memory but not FLOPs (still counted as FP32-equivalent).
  • Gradient checkpointing: Reduces memory but may slightly increase FLOPs (negligible here).
  • Overhead: Communication, data loading, etc., are not included (typically <10% of total FLOPs).

8. Final Estimate

The total FLOPs to train GPT-3 is approximately: ~7 × 10¹⁹ FLOPs (70 exaFLOPs).

This aligns with independent estimates (e.g., Epoch AI's analysis suggests ~3.14 × 10²³ FLOPs, but this includes a higher token count; our estimate assumes 300B tokens).


Key Takeaways

  1. The bulk of FLOPs come from the feed-forward layers and attention mechanisms.
  2. The backward pass is 2× the forward pass in FLOPs.
  3. The optimizer adds a small but non-negligible overhead (~1-2% of total FLOPs).
  4. The final estimate is sensitive to the number of training tokens and batch size.
Try this prompt
Claude 3.7 Sonnet

Claude 3.7 Sonnet

Anthropic · Feb 2025text

Estimating FLOPs for GPT-3 Training

I'll estimate the total number of FLOPs (Floating Point Operations) required to train GPT-3 by breaking this down step by step.

GPT-3 Architecture Facts

From what I recall about GPT-3:

  • Parameters: ~175 billion parameters
  • Training tokens: ~300-400 billion tokens
  • Architecture: Transformer decoder-only
  • Context length: 2048 tokens

Step 1: FLOPs per Forward Pass

In a transformer model, the main computational components are:

  • Self-attention: O(s²d) where s is sequence length and d is model dimension
  • Feed-forward networks: O(sd²)

For GPT-3, if we assume:

  • Sequence length (s) = 2048
  • Model dimension (d) ≈ 12288 (estimated based on parameter count)
  • Number of layers ≈ 96 (estimated)

FLOPs per token in forward pass:

  • Self-attention: ~2 × 2048² × 12288 × 96 ≈ 4.8 × 10¹²
  • Feed-forward: ~2 × 2048 × 12288² × 96 ≈ 5.9 × 10¹³
  • Total per forward pass: ~6.4 × 10¹³ FLOPs

Step 2: FLOPs per Backward Pass

The backward pass typically requires about 2× the computation of the forward pass:

  • Backward pass: ~2 × 6.4 × 10¹³ ≈ 1.3 × 10¹⁴ FLOPs

Step 3: FLOPs per Training Step

For each training step:

  • Forward + backward: ~6.4 × 10¹³ + 1.3 × 10¹⁴ ≈ 1.9 × 10¹⁴ FLOPs

Step 4: Total Training FLOPs

If GPT-3 was trained on ~300 billion tokens:

  • Total FLOPs: 1.9 × 10¹⁴ × 3 × 10¹¹ ≈ 5.7 × 10²⁵ FLOPs

Accounting for optimization overhead, gradient accumulation, and other factors, we might round up to:

  • Total training FLOPs: ~10²⁶ FLOPs

This is in the same order of magnitude as other estimates I've seen, which typically place GPT-3 training at around 3-6 × 10²³ FLOPs. My estimate is a bit higher, which could be due to overestimating some of the architectural parameters or not accounting for optimizations like mixed precision training.

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2 / 35
02

AI Board Game Logicreasoning

Tests an AI's ability to understand game rules and strategy

Bert-Nebulon Alpha

Bert-Nebulon Alpha

Openrouter · Nov 2025svg
Try this prompt
Claude 3.7 Sonnet

Claude 3.7 Sonnet

Anthropic · Feb 2025svg
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3 / 35
03

Logic Puzzlereasoning

Tests an AI's ability to solve a simple but potentially confusing logic puzzle

Bert-Nebulon Alpha

Bert-Nebulon Alpha

Openrouter · Nov 2025text

Alright, let's tackle this problem step by step. The question is:

"Sally (a girl) has 3 brothers. Each brother has 2 sisters. How many sisters does Sally have?"

At first glance, it might seem a bit confusing, but let's break it down to understand it better.

Understanding the Problem

We have a family with several children, and we're given information about Sally and her brothers. Here's what we know:

  1. Sally is a girl.
  2. Sally has 3 brothers.
  3. Each brother has 2 sisters.

We need to determine: How many sisters does Sally have?

Breaking Down the Information

First, let's list out the children in the family based on the information given.

  1. Sally: She is one girl in the family.
  2. Sally's brothers: There are 3 brothers.

So far, we have:

  • Girls: Sally
  • Boys: Brother 1, Brother 2, Brother 3

Now, the next piece of information is: "Each brother has 2 sisters."

This means that if we take any one of the brothers, he has 2 sisters.

Determining the Sisters

Let's think about what "each brother has 2 sisters" implies.

  • For Brother 1: He has 2 sisters.
  • For Brother 2: He has 2 sisters.
  • For Brother 3: He has 2 sisters.

Now, who are these sisters? They are the female children in the family.

We already know that Sally is one sister. If each brother has 2 sisters, and Sally is one of them, who is the other sister?

This suggests that there must be another girl in the family besides Sally to make the count of sisters equal to 2 for each brother.

Let's denote the other sister as "Sister 2."

Now, the family looks like:

  • Girls: Sally, Sister 2
  • Boys: Brother 1, Brother 2, Brother 3

Now, let's check if this satisfies the condition that each brother has 2 sisters.

  • For any brother, his sisters are Sally and Sister 2. That's 2 sisters. This checks out.

Verifying the Number of Sisters Sally Has

Now, the question is asking: How many sisters does Sally have?

From our current family setup:

  • Sally's siblings are: Brother 1, Brother 2, Brother 3, and Sister 2.

So, Sally has one sister (Sister 2).

But wait, let's double-check to ensure we haven't missed anything.

Re-evaluating the Family Structure

Initially, we thought:

  • Sally is one girl.
  • 3 brothers.
  • Each brother has 2 sisters, implying another sister besides Sally.

But is it possible that Sally is the only sister, and the count is somehow different?

Let's explore that.

If Sally is the only sister:

  • Sisters: Sally
  • Brothers: 3

Then, each brother would have only 1 sister (Sally), but the problem states that each brother has 2 sisters. This doesn't match, so Sally cannot be the only sister.

Therefore, there must be at least one more sister besides Sally to make the count of sisters equal to 2 for each brother.

Considering More Sisters

Could there be more than one other sister? Let's see.

If there are two other sisters besides Sally (let's call them Sister 2 and Sister 3), then:

  • Sisters: Sally, Sister 2, Sister 3
  • Brothers: 3

Now, each brother would have 3 sisters, but the problem says each brother has 2 sisters. This is too many, so we can't have more than one other sister.

Therefore, the only possibility is:

  • Sisters: Sally, Sister 2
  • Brothers: 3

This gives each brother exactly 2 sisters (Sally and Sister 2), which matches the given information.

Final Count of Sally's Sisters

Now, the question is: How many sisters does Sally have?

Sally's siblings are:

  • Brothers: 3
  • Sisters: Sister 2

So, Sally has 1 sister.

Potential Missteps

Initially, one might think that since each brother has 2 sisters, and there are 3 brothers, there are 6 sister instances (3 brothers × 2 sisters each), leading to the idea that there are 6 sisters. But this would be incorrect because all brothers share the same sisters; the sisters aren't unique to each brother.

Another possible confusion is thinking that Sally is not included in the count of sisters for the brothers, leading to an incorrect addition. But Sally is indeed one of the sisters that the brothers have.

Conclusion

After carefully analyzing the family structure and ensuring that all given conditions are met, we conclude that:

Sally has 1 sister.

Try this prompt
Claude 3.7 Sonnet

Claude 3.7 Sonnet

Anthropic · Feb 2025text
Nothing here. The model returned empty. We stared at it for a while.
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4 / 35
04

Math Misconception Testreasoning

Tests an AI's understanding of number representation

Bert-Nebulon Alpha

Bert-Nebulon Alpha

Openrouter · Nov 2025text

No, 9.11 is not greater than 9.9.

Here's the comparison:

  • 9.9 is the same as 9.90.
  • 9.11 is less than 9.90.

So, 9.11 < 9.9.

Try this prompt
Claude 3.7 Sonnet

Claude 3.7 Sonnet

Anthropic · Feb 2025text
Nothing here. The model returned empty. We stared at it for a while.
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5 / 35
05

Stochastic Consistency Testanalysis

Tests an AI's randomness and creativity

Bert-Nebulon Alpha

Bert-Nebulon Alpha

Openrouter · Nov 2025text

Here are five jokes for you:

  1. Why don’t skeletons fight each other? They don’t have the guts.

  2. Why did the scarecrow win an award? Because he was outstanding in his field!

  3. What do you call a fake noodle? An impasta.

  4. Why can’t you trust an atom? Because they make up everything!

  5. Why did the bicycle fall over? Because it was two-tired!

Uniqueness Check:

All five jokes are unique—they’re distinct in setup, punchline, and theme. No repeats here!

Want more? I can generate even weirder ones. 😄

Try this prompt
Claude 3.7 Sonnet

Claude 3.7 Sonnet

Anthropic · Feb 2025text
Nothing here. The model returned empty. We stared at it for a while.
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6 / 35
06

SVG Layout Challengeimage generation

Tests an AI's ability to generate vector graphics

Bert-Nebulon Alpha

Bert-Nebulon Alpha

Openrouter · Nov 2025svg
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Claude 3.7 Sonnet

Claude 3.7 Sonnet

Anthropic · Feb 2025svg
Nothing here. The model returned empty. We stared at it for a while.
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Sponsored
7 / 35
07

Xbox Controller SVG Artimage generation

Tests an AI's ability to create detailed SVG illustrations of gaming hardware

Bert-Nebulon Alpha

Bert-Nebulon Alpha

Openrouter · Nov 2025svg
Nothing here. The model returned empty. We stared at it for a while.
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Claude 3.7 Sonnet

Claude 3.7 Sonnet

Anthropic · Feb 2025svg
Nothing here. The model returned empty. We stared at it for a while.
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8 / 35
08

Generate a Stand-Up Routineconversation

Tests an AI's humor and creative writing ability

Bert-Nebulon Alpha

Bert-Nebulon Alpha

Openrouter · Nov 2025text
Nothing here. The model returned empty. We stared at it for a while.
Try this prompt
Claude 3.7 Sonnet

Claude 3.7 Sonnet

Anthropic · Feb 2025text
Nothing here. The model returned empty. We stared at it for a while.
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9 / 35
09

Realistic AI Interviewconversation

Tests an AI's ability to simulate personalities and predict future trends

Bert-Nebulon Alpha

Bert-Nebulon Alpha

Openrouter · Nov 2025text
Nothing here. The model returned empty. We stared at it for a while.
Try this prompt
Claude 3.7 Sonnet

Claude 3.7 Sonnet

Anthropic · Feb 2025text
Nothing here. The model returned empty. We stared at it for a while.
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10 / 35
10

Satirical Fake News Headlineconversation

Tests an AI's humor and understanding of current events

Bert-Nebulon Alpha

Bert-Nebulon Alpha

Openrouter · Nov 2025text
Nothing here. The model returned empty. We stared at it for a while.
Try this prompt
Claude 3.7 Sonnet

Claude 3.7 Sonnet

Anthropic · Feb 2025text
Nothing here. The model returned empty. We stared at it for a while.
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11 / 35
11

Character Voice Testconversation

Tests an AI's ability to write in distinct character voices

Bert-Nebulon Alpha

Bert-Nebulon Alpha

Openrouter · Nov 2025text
Nothing here. The model returned empty. We stared at it for a while.
Try this prompt
Claude 3.7 Sonnet

Claude 3.7 Sonnet

Anthropic · Feb 2025text
Nothing here. The model returned empty. We stared at it for a while.
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12 / 35
12

Minimalist Landing Pageweb design

Tests an AI's ability to generate a complete, working landing page

Bert-Nebulon Alpha

Bert-Nebulon Alpha

Openrouter · Nov 2025website
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Claude 3.7 Sonnet

Claude 3.7 Sonnet

Anthropic · Feb 2025website
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This matchup has more rounds

23+ more head-to-head results. Free. Not a trick.

Free account. No card required. By continuing, you agree to Rival's Terms and Privacy Policy

Our Verdict
Claude 3.7 Sonnet
Claude 3.7 SonnetWinner
Bert-Nebulon Alpha
Bert-Nebulon AlphaRunner-up

Pick Claude 3.7 Sonnet. In 1 blind votes, Claude 3.7 Sonnet wins 100% of the time. That's not luck.

Clear winner
Writing DNA

Style Comparison

Similarity
100%

Bert-Nebulon Alpha uses 42.4x more emoji

Bert-Nebulon Alpha
Claude 3.7 Sonnet
55%Vocabulary62%
21wSentence Length35w
0.28Hedging0.99
10.9Bold1.2
5.7Lists4.3
0.42Emoji0.00
1.40Headings1.78
0.04Transitions0.23
Based on 14 + 13 text responses
vs

Ask them anything yourself

Bert-Nebulon AlphaClaude 3.7 Sonnet

Some models write identically. You are paying for the brand.

178 models fingerprinted across 32 writing dimensions. Free research.

Model Similarity Index

185x

price gap between models that write identically

178

models

12

clone pairs

32

dimensions

Devstral M / S
95.7%
Qwen3 Coder / Flash
95.6%
GPT-5.4 / Mini
93.3%
Read the full reportor download the 14-slide PDF

279 AI models invented the same fake scientist.

We read every word. 250 models. 2.14 million words. This is what we found.

AI Hallucination Index 2026
Free preview13 of 58 slides
Download the free previewor get all 58 slides for $49
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